| "use strict"; |
| Object.defineProperty(exports, "__esModule", { value: true }); |
| exports.compile = void 0; |
| var boolbase_1 = require("boolbase"); |
| /** |
| * Returns a function that checks if an elements index matches the given rule |
| * highly optimized to return the fastest solution. |
| * |
| * @param parsed A tuple [a, b], as returned by `parse`. |
| * @returns A highly optimized function that returns whether an index matches the nth-check. |
| * @example |
| * const check = nthCheck.compile([2, 3]); |
| * |
| * check(0); // `false` |
| * check(1); // `false` |
| * check(2); // `true` |
| * check(3); // `false` |
| * check(4); // `true` |
| * check(5); // `false` |
| * check(6); // `true` |
| */ |
| function compile(parsed) { |
| var a = parsed[0]; |
| // Subtract 1 from `b`, to convert from one- to zero-indexed. |
| var b = parsed[1] - 1; |
| /* |
| * When `b <= 0`, `a * n` won't be lead to any matches for `a < 0`. |
| * Besides, the specification states that no elements are |
| * matched when `a` and `b` are 0. |
| * |
| * `b < 0` here as we subtracted 1 from `b` above. |
| */ |
| if (b < 0 && a <= 0) |
| return boolbase_1.falseFunc; |
| // When `a` is in the range -1..1, it matches any element (so only `b` is checked). |
| if (a === -1) |
| return function (index) { return index <= b; }; |
| if (a === 0) |
| return function (index) { return index === b; }; |
| // When `b <= 0` and `a === 1`, they match any element. |
| if (a === 1) |
| return b < 0 ? boolbase_1.trueFunc : function (index) { return index >= b; }; |
| /* |
| * Otherwise, modulo can be used to check if there is a match. |
| * |
| * Modulo doesn't care about the sign, so let's use `a`s absolute value. |
| */ |
| var absA = Math.abs(a); |
| // Get `b mod a`, + a if this is negative. |
| var bMod = ((b % absA) + absA) % absA; |
| return a > 1 |
| ? function (index) { return index >= b && index % absA === bMod; } |
| : function (index) { return index <= b && index % absA === bMod; }; |
| } |
| exports.compile = compile; |