qapi: Use an explicit input file
Use an explicit input file on the command-line instead of reading from standard
input.
It also outputs the proper file name when there's an error.
Signed-off-by: Lluís Vilanova <vilanova@ac.upc.edu>
Reviewed-by: Eric Blake <eblake@redhat.com>
Reviewed-by: Markus Armbruster <armbru@redhat.com>
Signed-off-by: Luiz Capitulino <lcapitulino@redhat.com>
diff --git a/scripts/qapi-commands.py b/scripts/qapi-commands.py
index 9734ab0..8d9096f 100644
--- a/scripts/qapi-commands.py
+++ b/scripts/qapi-commands.py
@@ -369,9 +369,10 @@
try:
- opts, args = getopt.gnu_getopt(sys.argv[1:], "chp:o:m",
+ opts, args = getopt.gnu_getopt(sys.argv[1:], "chp:i:o:m",
["source", "header", "prefix=",
- "output-dir=", "type=", "middle"])
+ "input-file=", "output-dir=",
+ "type=", "middle"])
except getopt.GetoptError, err:
print str(err)
sys.exit(1)
@@ -389,6 +390,8 @@
for o, a in opts:
if o in ("-p", "--prefix"):
prefix = a
+ elif o in ("-i", "--input-file"):
+ input_file = a
elif o in ("-o", "--output-dir"):
output_dir = a + "/"
elif o in ("-t", "--type"):
@@ -420,7 +423,7 @@
if e.errno != errno.EEXIST:
raise
-exprs = parse_schema(sys.stdin)
+exprs = parse_schema(input_file)
commands = filter(lambda expr: expr.has_key('command'), exprs)
commands = filter(lambda expr: not expr.has_key('gen'), commands)